64 lines
1.5 KiB
Bash
Executable File
64 lines
1.5 KiB
Bash
Executable File
#!/bin/bash
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testpath1=/faronear
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testpath2=~/faronear.git
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testpath3=~/faronear
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testpath4=/mnt/d/faronear
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if [ "$1" ]
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then
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FONPATH=$1
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elif [ -d $testpath1 ]
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then
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FONPATH=$testpath1
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elif [ -d $testpath2 ]
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then
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FONPATH=$testpath2
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elif [ -d $testpath3 ]
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then
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FONPATH=$testpath3
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elif [ -d $testpath4 ]
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then
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FONPATH=$testpath4
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else
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echo "=== Enter [target path] or leave [blank] for default to '.'"
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read -p ">>> " FONPATH
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echo ""
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if [ ! "$FONPATH" ]
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then
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FONPATH=.
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fi
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fi
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if [ ! -d "$FONPATH" ]
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then
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echo "*** [$FONPATH] not exist! Exit now. ***"
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exit
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fi
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pushd $FONPATH
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echo "*** Starting from [`pwd`] ***"
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echo ""
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# for org in `ls -F | grep '/$' | grep -v '~'` ## 首先过滤出所有子目录，然后过滤出所有不含 ~ 的子目录。注意 for ??? in `ls ???` 是按照空行以及空格进行分割的，因此最后筛选出的目录名不能含有空格，否则就被分割成多个了。
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ls -F | grep '/$' | grep -v '=' | while read org ## 换用这种方法，可以成功过滤出含有空格的完整目录名
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do
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echo "======== entering [$FONPATH/$org] ========"
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echo ""
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cd "$org";
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for repo in * ## for ??? in * 是分割成一个个目录名的，即使目录名含有空格
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do
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if ( [ -f "$repo/package.json" ] && grep -q '"boot"' "$repo/package.json" )
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then
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echo "<<<< npm booting: [$org/$repo] <<<<"
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cd "$repo"
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npm run boot
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echo ">>>> npm booted: [$org/$repo] >>>>"
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echo ""
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cd ..
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fi
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done
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cd ..;
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done
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popd
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